std::list::splice
void splice(const_iterator pos, list& other); |
(1) | |
void splice(const_iterator pos, list&& other); |
(1) | (since C++11) |
void splice(const_iterator pos, list& other, const_iterator it); |
(2) | |
void splice(const_iterator pos, list&& other, const_iterator it); |
(2) | (since C++11) |
void splice(const_iterator pos, list& other, const_iterator first, const_iterator last); |
(3) | |
void splice(const_iterator pos, list&& other, const_iterator first, const_iterator last); |
(3) | (since C++11) |
Moves elements from one list to another.
No elements are copied. The behavior is undefined if: get_allocator() != other.get_allocator(). No iterators or references become invalidated, the iterators to moved elements now refer into *this, not into other.
1) Moves all elements from other into *this. The elements are inserted before the element pointed to by pos. The container other becomes empty after the operation. The behavior is undefined if this == &other.
2) Moves the element pointed to by it from other into *this. The element is inserted before the element pointed to by pos.
3) Moves the elements in the range [first, last) from other into *this. The elements are inserted before the element pointed to by pos. The behavior is undefined if pos is an iterator in the range [first,last).
Contents |
[edit] Parameters
pos | - | element before which the content will be inserted |
other | - | another container to move the content from |
it | - | the element to move from other to *this |
first, last | - | the range of elements to move from other to *this |
[edit] Return value
(none)
[edit] Example
#include <iostream> #include <list> std::ostream& operator<<(std::ostream& ostr, const std::list<int>& list) { for (auto &i : list) { ostr << " " << i; } return ostr; } int main () { std::list<int> list1 = { 1, 2, 3, 4, 5 }; std::list<int> list2 = { 10, 20, 30, 40, 50 }; auto it = list1.begin(); std::advance(it, 2); list1.splice(it, list2); std::cout << "list1: " << list1 << "\n"; std::cout << "list2: " << list2 << "\n"; list2.splice(list2.begin(), list1, it, list1.end()); std::cout << "list1: " << list1 << "\n"; std::cout << "list2: " << list2 << "\n"; }
Output:
list1: 1 2 10 20 30 40 50 3 4 5 list2: list1: 1 2 10 20 30 40 50 list2: 3 4 5
[edit] Complexity
1-2) Constant.
3) Constant if this == &other, otherwise linear in std::distance(first, last).
[edit] See also
merges two sorted lists (public member function) | |
removes elements satisfying specific criteria (public member function) |