std::deque::erase
From cppreference.com
iterator erase( iterator pos ); iterator erase( const_iterator pos ); |
(1) | (until C++11) (since C++11) |
iterator erase( iterator first, iterator last ); iterator erase( const_iterator first, const_iterator last ); |
(2) | (until C++11) (since C++11) |
Removes specified elements from the container.
1) Removes the element at pos.
2) Removes the elements in the range [first; last).
All iterators and references are invalidated, unless the erased elements are at the end or the beginning of the container, in which case only the iterators and references to the erased elements are invalidated. If the last element is erased or invalidated, the past-the-end iterator is also invalidated. (since C++11).This section is incomplete Reason: mark the change between C++03 and C++11 |
Contents |
[edit] Parameters
pos | - | iterator to the element to remove |
first, last | - | range of elements to remove |
[edit] Return value
iterator following the last removed element.
[edit] Example
#include <deque> #include <iostream> int main( ) { std::deque<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()+2, c.begin()+5); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; }
Output:
0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 6 7 8 9
[edit] Complexity
1) linear in the distance between position and last.
2) linear in distance between position and the end of the container.
[edit] See also
clears the contents (public member function) |